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3421324001335 = 55631215390409
BaseRepresentation
bin110001110010010110110…
…011010100000000110111
3110010002000221201011002011
4301302112303110000313
5422023332421020320
611135422355025051
7502116412115152
oct61622663240067
913102027634064
103421324001335
1110a9a80228979
124730aa59b187
131ba824c355c6
14bb84314cc99
155dee323a05a
hex31c96cd4037

3421324001335 has 8 divisors (see below), whose sum is σ = 4112881147440. Its totient is φ = 2732197637184.

The previous prime is 3421324001297. The next prime is 3421324001399. The reversal of 3421324001335 is 5331004231243.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3421324001335 - 29 = 3421324000823 is a prime.

It is a super-2 number, since 2×34213240013352 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3421324001297 and 3421324001306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 607692390 + ... + 607698019.

It is an arithmetic number, because the mean of its divisors is an integer number (514110143430).

Almost surely, 23421324001335 is an apocalyptic number.

3421324001335 is a deficient number, since it is larger than the sum of its proper divisors (691557146105).

3421324001335 is a wasteful number, since it uses less digits than its factorization.

3421324001335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1215390977.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 3421324001335 its reverse (5331004231243), we get a palindrome (8752328232578).

The spelling of 3421324001335 in words is "three trillion, four hundred twenty-one billion, three hundred twenty-four million, one thousand, three hundred thirty-five".

Divisors: 1 5 563 2815 1215390409 6076952045 684264800267 3421324001335