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34215240637051 is a prime number
BaseRepresentation
bin1111100011110010110110…
…10000111001101001111011
311111010221111221121201120121
413301321123100321221323
513441040303100341201
6200434133051034111
710130653362543445
oct761713320715173
9144127457551517
1034215240637051
11a9a1669394031
123a07186a3b937
131612638bb7986
14864052951495
153e503c2029a1
hex1f1e5b439a7b

34215240637051 has 2 divisors, whose sum is σ = 34215240637052. Its totient is φ = 34215240637050.

The previous prime is 34215240637009. The next prime is 34215240637069. The reversal of 34215240637051 is 15073604251243.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 34215240637051 - 219 = 34215240112763 is a prime.

It is a super-2 number, since 2×342152406370512 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34215240636989 and 34215240637007.

It is not a weakly prime, because it can be changed into another prime (34215240637001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17107620318525 + 17107620318526.

It is an arithmetic number, because the mean of its divisors is an integer number (17107620318526).

Almost surely, 234215240637051 is an apocalyptic number.

34215240637051 is a deficient number, since it is larger than the sum of its proper divisors (1).

34215240637051 is an equidigital number, since it uses as much as digits as its factorization.

34215240637051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 43.

Adding to 34215240637051 its reverse (15073604251243), we get a palindrome (49288844888294).

The spelling of 34215240637051 in words is "thirty-four trillion, two hundred fifteen billion, two hundred forty million, six hundred thirty-seven thousand, fifty-one".