Base | Representation |
---|---|
bin | 1001111101100110111… |
… | …01000000101101010001 |
3 | 1012201120101120102002001 |
4 | 10332303131000231101 |
5 | 21102024131034441 |
6 | 421131222354001 |
7 | 33505560464545 |
oct | 4766335005521 |
9 | 1181511512061 |
10 | 342313143121 |
11 | 1221a0932a74 |
12 | 56413b8b901 |
13 | 263841a86c1 |
14 | 127d49dda25 |
15 | 8d872b1731 |
hex | 4fb3740b51 |
342313143121 has 2 divisors, whose sum is σ = 342313143122. Its totient is φ = 342313143120.
The previous prime is 342313143113. The next prime is 342313143143. The reversal of 342313143121 is 121341313243.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 341568944721 + 744198400 = 584439^2 + 27280^2 .
It is a cyclic number.
It is not a de Polignac number, because 342313143121 - 23 = 342313143113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 342313143121.
It is not a weakly prime, because it can be changed into another prime (342313143191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171156571560 + 171156571561.
It is an arithmetic number, because the mean of its divisors is an integer number (171156571561).
Almost surely, 2342313143121 is an apocalyptic number.
It is an amenable number.
342313143121 is a deficient number, since it is larger than the sum of its proper divisors (1).
342313143121 is an equidigital number, since it uses as much as digits as its factorization.
342313143121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 28.
Adding to 342313143121 its reverse (121341313243), we get a palindrome (463654456364).
The spelling of 342313143121 in words is "three hundred forty-two billion, three hundred thirteen million, one hundred forty-three thousand, one hundred twenty-one".
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