Base | Representation |
---|---|
bin | 1001111101110101001… |
… | …10101110110111100001 |
3 | 1012201212202100110212122 |
4 | 10332322212232313201 |
5 | 21102300340211001 |
6 | 421151150234025 |
7 | 33511545411422 |
oct | 4767246566741 |
9 | 1181782313778 |
10 | 342433132001 |
11 | 122252637434 |
12 | 564481b5915 |
13 | 263a2cca53c |
14 | 12806915649 |
15 | 8d92ab3b1b |
hex | 4fba9aede1 |
342433132001 has 2 divisors, whose sum is σ = 342433132002. Its totient is φ = 342433132000.
The previous prime is 342433131983. The next prime is 342433132007. The reversal of 342433132001 is 100231334243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 307669902400 + 34763229601 = 554680^2 + 186449^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-342433132001 is a prime.
It is not a weakly prime, because it can be changed into another prime (342433132007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171216566000 + 171216566001.
It is an arithmetic number, because the mean of its divisors is an integer number (171216566001).
Almost surely, 2342433132001 is an apocalyptic number.
It is an amenable number.
342433132001 is a deficient number, since it is larger than the sum of its proper divisors (1).
342433132001 is an equidigital number, since it uses as much as digits as its factorization.
342433132001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 342433132001 its reverse (100231334243), we get a palindrome (442664466244).
The spelling of 342433132001 in words is "three hundred forty-two billion, four hundred thirty-three million, one hundred thirty-two thousand, one".
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