Base | Representation |
---|---|
bin | 100110111011100110100110… |
… | …0101001001001001010000011 |
3 | 1122220111021001222210001222211 |
4 | 1031313031030221021022003 |
5 | 324341042411233044303 |
6 | 3212152142503042551 |
7 | 132062466533301013 |
oct | 11567151451111203 |
9 | 1586437058701884 |
10 | 342443323331203 |
11 | 9a1274415a5726 |
12 | 324a7988140457 |
13 | 119103612b52a3 |
14 | 607c4b9661c43 |
15 | 298cb0b59966d |
hex | 137734ca49283 |
342443323331203 has 2 divisors, whose sum is σ = 342443323331204. Its totient is φ = 342443323331202.
The previous prime is 342443323331191. The next prime is 342443323331257. The reversal of 342443323331203 is 302133323344243.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 342443323331203 - 25 = 342443323331171 is a prime.
It is not a weakly prime, because it can be changed into another prime (342443323331273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171221661665601 + 171221661665602.
It is an arithmetic number, because the mean of its divisors is an integer number (171221661665602).
Almost surely, 2342443323331203 is an apocalyptic number.
342443323331203 is a deficient number, since it is larger than the sum of its proper divisors (1).
342443323331203 is an equidigital number, since it uses as much as digits as its factorization.
342443323331203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1119744, while the sum is 40.
Adding to 342443323331203 its reverse (302133323344243), we get a palindrome (644576646675446).
The spelling of 342443323331203 in words is "three hundred forty-two trillion, four hundred forty-three billion, three hundred twenty-three million, three hundred thirty-one thousand, two hundred three".
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