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34300400014 = 217150200007
BaseRepresentation
bin11111111100011101…
…101001000110001110
310021112110020212011201
4133330131221012032
51030221400300024
623431332340114
72322665406136
oct377435510616
9107473225151
1034300400014
1113601755231
12679317463a
1333082c46aa
141935637ac6
15d5b43b744
hex7fc76918e

34300400014 has 4 divisors (see below), whose sum is σ = 51450600024. Its totient is φ = 17150200006.

The previous prime is 34300399967. The next prime is 34300400051. The reversal of 34300400014 is 41000400343.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41000400343 = 75857200049.

It is a super-3 number, since 3×343004000143 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 34300399964 and 34300400000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8575100002 + ... + 8575100005.

It is an arithmetic number, because the mean of its divisors is an integer number (12862650006).

Almost surely, 234300400014 is an apocalyptic number.

34300400014 is a deficient number, since it is larger than the sum of its proper divisors (17150200010).

34300400014 is a wasteful number, since it uses less digits than its factorization.

34300400014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17150200009.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 34300400014 its reverse (41000400343), we get a palindrome (75300800357).

The spelling of 34300400014 in words is "thirty-four billion, three hundred million, four hundred thousand, fourteen".

Divisors: 1 2 17150200007 34300400014