Base | Representation |
---|---|
bin | 100111000000101011011111… |
… | …0101011010111111001011011 |
3 | 1122222221221221202110010110021 |
4 | 1032001112332223113321123 |
5 | 324434010302413023233 |
6 | 3213444450422131311 |
7 | 132164056250432245 |
oct | 11601267653277133 |
9 | 1588857852403407 |
10 | 343141021220443 |
11 | 9a3763208a1446 |
12 | 3259b041880b37 |
13 | 119610a081b3c4 |
14 | 60a4184d09095 |
15 | 29a0d434b4e2d |
hex | 13815bead7e5b |
343141021220443 has 4 divisors (see below), whose sum is σ = 345760418329128. Its totient is φ = 340521624111760.
The previous prime is 343141021220419. The next prime is 343141021220453. The reversal of 343141021220443 is 344022120141343.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 343141021220443 - 217 = 343141021089371 is a prime.
It is a super-2 number, since 2×3431410212204432 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 343141021220399 and 343141021220408.
It is not an unprimeable number, because it can be changed into a prime (343141021220453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1309698554146 + ... + 1309698554407.
It is an arithmetic number, because the mean of its divisors is an integer number (86440104582282).
Almost surely, 2343141021220443 is an apocalyptic number.
343141021220443 is a deficient number, since it is larger than the sum of its proper divisors (2619397108685).
343141021220443 is a wasteful number, since it uses less digits than its factorization.
343141021220443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2619397108684.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 343141021220443 its reverse (344022120141343), we get a palindrome (687163141361786).
The spelling of 343141021220443 in words is "three hundred forty-three trillion, one hundred forty-one billion, twenty-one million, two hundred twenty thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •