Base | Representation |
---|---|
bin | 1100110010100110… |
… | …0010011011101001 |
3 | 22212021121212121112 |
4 | 3030221202123221 |
5 | 24012430103001 |
6 | 1324410320105 |
7 | 151040524034 |
oct | 31451423351 |
9 | 8767555545 |
10 | 3433441001 |
11 | 15020a7051 |
12 | 7b9a29035 |
13 | 4294340c3 |
14 | 247dd401b |
15 | 151660cbb |
hex | cca626e9 |
3433441001 has 2 divisors, whose sum is σ = 3433441002. Its totient is φ = 3433441000.
The previous prime is 3433440973. The next prime is 3433441043. The reversal of 3433441001 is 1001443343.
3433441001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3141714601 + 291726400 = 56051^2 + 17080^2 .
It is an emirp because it is prime and its reverse (1001443343) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3433441001 is a prime.
It is not a weakly prime, because it can be changed into another prime (3433441201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1716720500 + 1716720501.
It is an arithmetic number, because the mean of its divisors is an integer number (1716720501).
Almost surely, 23433441001 is an apocalyptic number.
It is an amenable number.
3433441001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3433441001 is an equidigital number, since it uses as much as digits as its factorization.
3433441001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
The square root of 3433441001 is about 58595.5715135538. The cubic root of 3433441001 is about 1508.6084282088.
Adding to 3433441001 its reverse (1001443343), we get a palindrome (4434884344).
The spelling of 3433441001 in words is "three billion, four hundred thirty-three million, four hundred forty-one thousand, one".
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