Base | Representation |
---|---|
bin | 1001111111101000110… |
… | …00010100101001101011 |
3 | 1012211101022021002001111 |
4 | 10333310120110221223 |
5 | 21111242010330011 |
6 | 421431253531151 |
7 | 33544555343302 |
oct | 4776430245153 |
9 | 1184338232044 |
10 | 343402433131 |
11 | 1226aa7a274a |
12 | 56678943ab7 |
13 | 264c8a795c4 |
14 | 12899551439 |
15 | 8decc2e121 |
hex | 4ff4614a6b |
343402433131 has 2 divisors, whose sum is σ = 343402433132. Its totient is φ = 343402433130.
The previous prime is 343402433081. The next prime is 343402433147. The reversal of 343402433131 is 131334204343.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 343402433131 - 29 = 343402432619 is a prime.
It is a super-2 number, since 2×3434024331312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 343402433093 and 343402433102.
It is not a weakly prime, because it can be changed into another prime (343402233131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171701216565 + 171701216566.
It is an arithmetic number, because the mean of its divisors is an integer number (171701216566).
Almost surely, 2343402433131 is an apocalyptic number.
343402433131 is a deficient number, since it is larger than the sum of its proper divisors (1).
343402433131 is an equidigital number, since it uses as much as digits as its factorization.
343402433131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 343402433131 its reverse (131334204343), we get a palindrome (474736637474).
The spelling of 343402433131 in words is "three hundred forty-three billion, four hundred two million, four hundred thirty-three thousand, one hundred thirty-one".
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