Base | Representation |
---|---|
bin | 110001111110011110101… |
… | …001000100000110100111 |
3 | 110011022122002102110101120 |
4 | 301332132221010012213 |
5 | 422232012122344333 |
6 | 11145414134225023 |
7 | 503060105014350 |
oct | 61763651040647 |
9 | 13138562373346 |
10 | 3434340434343 |
11 | 110454a707725 |
12 | 4757217b5173 |
13 | 1bbb1a83bc80 |
14 | bc319b54d27 |
15 | 5e505d35db3 |
hex | 31f9ea441a7 |
3434340434343 has 64 divisors (see below), whose sum is σ = 5869685348352. Its totient is φ = 1737735068160.
The previous prime is 3434340434341. The next prime is 3434340434353.
3434340434343 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3434340434343 - 21 = 3434340434341 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3434340434295 and 3434340434304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3434340434341) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1677196 + ... + 3111537.
It is an arithmetic number, because the mean of its divisors is an integer number (91713833568).
Almost surely, 23434340434343 is an apocalyptic number.
3434340434343 is a deficient number, since it is larger than the sum of its proper divisors (2435344914009).
3434340434343 is a wasteful number, since it uses less digits than its factorization.
3434340434343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4788864.
The product of its (nonzero) digits is 2985984, while the sum is 42.
It can be divided in two parts, 3434340 and 434343, that added together give a palindrome (3868683).
The spelling of 3434340434343 in words is "three trillion, four hundred thirty-four billion, three hundred forty million, four hundred thirty-four thousand, three hundred forty-three".
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