Base | Representation |
---|---|
bin | 110001111111010010101… |
… | …101111011100100011111 |
3 | 110011101212222102120010111 |
4 | 301333102231323210133 |
5 | 422240304304002333 |
6 | 11150040544350451 |
7 | 503120544166420 |
oct | 61772255734437 |
9 | 13141788376114 |
10 | 3435214125343 |
11 | 11049588aa700 |
12 | 475926315427 |
13 | 1bbc298536b0 |
14 | bc39dbc3647 |
15 | 5e5578b74cd |
hex | 31fd2b7b91f |
3435214125343 has 48 divisors (see below), whose sum is σ = 4693271220288. Its totient is φ = 2446418304000.
The previous prime is 3435214125337. The next prime is 3435214125353.
3435214125343 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 3435214125343 - 229 = 3434677254431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3435214125296 and 3435214125305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3435214125353) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 432346 + ... + 2656567.
It is an arithmetic number, because the mean of its divisors is an integer number (97776483756).
Almost surely, 23435214125343 is an apocalyptic number.
3435214125343 is a deficient number, since it is larger than the sum of its proper divisors (1258057094945).
3435214125343 is a wasteful number, since it uses less digits than its factorization.
3435214125343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3089056 (or 3089045 counting only the distinct ones).
The product of its digits is 518400, while the sum is 40.
The spelling of 3435214125343 in words is "three trillion, four hundred thirty-five billion, two hundred fourteen million, one hundred twenty-five thousand, three hundred forty-three".
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