Base | Representation |
---|---|
bin | 100000000010011101… |
… | …011010001010000001 |
3 | 10021210110112222022101 |
4 | 200002131122022001 |
5 | 1030423124031423 |
6 | 23445324510401 |
7 | 2325326456542 |
oct | 400235321201 |
9 | 107713488271 |
10 | 34401002113 |
11 | 13653518065 |
12 | 68009ab401 |
13 | 33230b926a |
14 | 1944b444c9 |
15 | d651ae7ad |
hex | 80275a281 |
34401002113 has 2 divisors, whose sum is σ = 34401002114. Its totient is φ = 34401002112.
The previous prime is 34401002107. The next prime is 34401002123. The reversal of 34401002113 is 31120010443.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34199844624 + 201157489 = 184932^2 + 14183^2 .
It is an emirp because it is prime and its reverse (31120010443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34401002113 - 29 = 34401001601 is a prime.
It is not a weakly prime, because it can be changed into another prime (34401002123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17200501056 + 17200501057.
It is an arithmetic number, because the mean of its divisors is an integer number (17200501057).
Almost surely, 234401002113 is an apocalyptic number.
It is an amenable number.
34401002113 is a deficient number, since it is larger than the sum of its proper divisors (1).
34401002113 is an equidigital number, since it uses as much as digits as its factorization.
34401002113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 34401002113 its reverse (31120010443), we get a palindrome (65521012556).
The spelling of 34401002113 in words is "thirty-four billion, four hundred one million, two thousand, one hundred thirteen".
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