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344010132131 is a prime number
BaseRepresentation
bin1010000000110001001…
…10100000101010100011
31012212221122202101100212
411000120212200222203
521114013043212011
6422011443004335
733565614606431
oct5003046405243
91185848671325
10344010132131
11122991829a26
12568083696ab
132659493c603
141291613dd51
158e3626d08b
hex50189a0aa3

344010132131 has 2 divisors, whose sum is σ = 344010132132. Its totient is φ = 344010132130.

The previous prime is 344010132119. The next prime is 344010132149. The reversal of 344010132131 is 131231010443.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 344010132131 - 226 = 343943023267 is a prime.

It is a super-2 number, since 2×3440101321312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 344010132097 and 344010132106.

It is not a weakly prime, because it can be changed into another prime (344010132101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172005066065 + 172005066066.

It is an arithmetic number, because the mean of its divisors is an integer number (172005066066).

Almost surely, 2344010132131 is an apocalyptic number.

344010132131 is a deficient number, since it is larger than the sum of its proper divisors (1).

344010132131 is an equidigital number, since it uses as much as digits as its factorization.

344010132131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 344010132131 its reverse (131231010443), we get a palindrome (475241142574).

The spelling of 344010132131 in words is "three hundred forty-four billion, ten million, one hundred thirty-two thousand, one hundred thirty-one".