Base | Representation |
---|---|
bin | 1010000000110001100… |
… | …01011100110111000011 |
3 | 1012212221212011002112002 |
4 | 11000120301130313003 |
5 | 21114014312001011 |
6 | 422012024254215 |
7 | 33565651153103 |
oct | 5003061346703 |
9 | 1185855132462 |
10 | 344013000131 |
11 | 122993408779 |
12 | 5680931136b |
13 | 26595404b58 |
14 | 12916689203 |
15 | 8e36637c3b |
hex | 5018c5cdc3 |
344013000131 has 2 divisors, whose sum is σ = 344013000132. Its totient is φ = 344013000130.
The previous prime is 344013000109. The next prime is 344013000137. The reversal of 344013000131 is 131000310443.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-344013000131 is a prime.
It is a super-2 number, since 2×3440130001312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (344013000137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172006500065 + 172006500066.
It is an arithmetic number, because the mean of its divisors is an integer number (172006500066).
Almost surely, 2344013000131 is an apocalyptic number.
344013000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
344013000131 is an equidigital number, since it uses as much as digits as its factorization.
344013000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 344013000131 its reverse (131000310443), we get a palindrome (475013310574).
The spelling of 344013000131 in words is "three hundred forty-four billion, thirteen million, one hundred thirty-one", and thus it is an aban number.
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