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34401411331 = 72702069619
BaseRepresentation
bin100000000010011110…
…111110000100000011
310021210111022202122121
4200002132332010003
51030423230130311
623445341345111
72325333112600
oct400236760403
9107714282577
1034401411331
1113653777561
126800b68197
1333232005c1
141944c0d6a7
15d65240b71
hex8027be103

34401411331 has 6 divisors (see below), whose sum is σ = 40017968340. Its totient is φ = 29486923956.

The previous prime is 34401411323. The next prime is 34401411347. The reversal of 34401411331 is 13311410443.

It is a happy number.

It is not a de Polignac number, because 34401411331 - 23 = 34401411323 is a prime.

It is a super-2 number, since 2×344014113312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34401411296 and 34401411305.

It is not an unprimeable number, because it can be changed into a prime (34401411311) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 351034761 + ... + 351034858.

It is an arithmetic number, because the mean of its divisors is an integer number (6669661390).

Almost surely, 234401411331 is an apocalyptic number.

34401411331 is a deficient number, since it is larger than the sum of its proper divisors (5616557009).

34401411331 is an equidigital number, since it uses as much as digits as its factorization.

34401411331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702069633 (or 702069626 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 34401411331 its reverse (13311410443), we get a palindrome (47712821774).

The spelling of 34401411331 in words is "thirty-four billion, four hundred one million, four hundred eleven thousand, three hundred thirty-one".

Divisors: 1 7 49 702069619 4914487333 34401411331