Base | Representation |
---|---|
bin | 100000000010100010… |
… | …011001100100100001 |
3 | 10021210120000102222200 |
4 | 200002202121210201 |
5 | 1030423442413213 |
6 | 23445412523413 |
7 | 2325343546101 |
oct | 400242314441 |
9 | 107716012880 |
10 | 34402310433 |
11 | 13654231017 |
12 | 6801320569 |
13 | 332345690a |
14 | 1944da5201 |
15 | d6536c273 |
hex | 802899921 |
34402310433 has 24 divisors (see below), whose sum is σ = 51066224352. Its totient is φ = 22305302208.
The previous prime is 34402310417. The next prime is 34402310447. The reversal of 34402310433 is 33401320443.
34402310433 is a `hidden beast` number, since 344 + 0 + 2 + 310 + 4 + 3 + 3 = 666.
It is not a de Polignac number, because 34402310433 - 24 = 34402310417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34402310397 and 34402310406.
It is not an unprimeable number, because it can be changed into a prime (34402310473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 100591 + ... + 280932.
It is an arithmetic number, because the mean of its divisors is an integer number (2127759348).
Almost surely, 234402310433 is an apocalyptic number.
It is an amenable number.
34402310433 is a deficient number, since it is larger than the sum of its proper divisors (16663913919).
34402310433 is a wasteful number, since it uses less digits than its factorization.
34402310433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 381805 (or 381802 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 27.
Adding to 34402310433 its reverse (33401320443), we get a palindrome (67803630876).
The spelling of 34402310433 in words is "thirty-four billion, four hundred two million, three hundred ten thousand, four hundred thirty-three".
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