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344040121 is a prime number
BaseRepresentation
bin10100100000011…
…010001010111001
3212222101001022201
4110200122022321
51201033240441
654045550201
711345202265
oct2440321271
9788331281
10344040121
11167224487
1297275361
135637a549
14339990a5
152030cc31
hex1481a2b9

344040121 has 2 divisors, whose sum is σ = 344040122. Its totient is φ = 344040120.

The previous prime is 344040107. The next prime is 344040127. The reversal of 344040121 is 121040443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 186186025 + 157854096 = 13645^2 + 12564^2 .

It is an emirp because it is prime and its reverse (121040443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 344040121 - 25 = 344040089 is a prime.

It is not a weakly prime, because it can be changed into another prime (344040127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172020060 + 172020061.

It is an arithmetic number, because the mean of its divisors is an integer number (172020061).

Almost surely, 2344040121 is an apocalyptic number.

It is an amenable number.

344040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

344040121 is an equidigital number, since it uses as much as digits as its factorization.

344040121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 344040121 is about 18548.3185491300. The cubic root of 344040121 is about 700.7068512962.

Adding to 344040121 its reverse (121040443), we get a palindrome (465080564).

The spelling of 344040121 in words is "three hundred forty-four million, forty thousand, one hundred twenty-one".