Base | Representation |
---|---|
bin | 1111101001010101010010… |
… | …11110001110001111110001 |
3 | 11111211010200122002122120121 |
4 | 13310222221132032033301 |
5 | 14002200012004010022 |
6 | 201101403300410241 |
7 | 10150501065602605 |
oct | 764525136161761 |
9 | 144733618078517 |
10 | 34405531313137 |
11 | aa65338526496 |
12 | 3a380329a6981 |
13 | 162757380156a |
14 | 86d345337505 |
15 | 3e9e780852c7 |
hex | 1f4aa978e3f1 |
34405531313137 has 2 divisors, whose sum is σ = 34405531313138. Its totient is φ = 34405531313136.
The previous prime is 34405531313113. The next prime is 34405531313149. The reversal of 34405531313137 is 73131313550443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34294188303376 + 111343009761 = 5856124^2 + 333681^2 .
It is a cyclic number.
It is not a de Polignac number, because 34405531313137 - 215 = 34405531280369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34405531313093 and 34405531313102.
It is not a weakly prime, because it can be changed into another prime (34405531313107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17202765656568 + 17202765656569.
It is an arithmetic number, because the mean of its divisors is an integer number (17202765656569).
Almost surely, 234405531313137 is an apocalyptic number.
It is an amenable number.
34405531313137 is a deficient number, since it is larger than the sum of its proper divisors (1).
34405531313137 is an equidigital number, since it uses as much as digits as its factorization.
34405531313137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 43.
The spelling of 34405531313137 in words is "thirty-four trillion, four hundred five billion, five hundred thirty-one million, three hundred thirteen thousand, one hundred thirty-seven".
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