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344102120304113 is a prime number
BaseRepresentation
bin100111000111101011000010…
…0101001011010110111110001
31200010100211201101221020210102
41032033112010221122313301
5330100232120244212423
63215502155355042145
7132323362215026123
oct11617260451326761
91603324641836712
10344102120304113
119a706987208106
1232715367a40355
1311a008c9654252
1460d88bab25213
1529bad44998c28
hex138f584a5adf1

344102120304113 has 2 divisors, whose sum is σ = 344102120304114. Its totient is φ = 344102120304112.

The previous prime is 344102120304071. The next prime is 344102120304139. The reversal of 344102120304113 is 311403021201443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 304584590331904 + 39517529972209 = 17452352^2 + 6286297^2 .

It is a cyclic number.

It is not a de Polignac number, because 344102120304113 - 218 = 344102120041969 is a prime.

It is a super-2 number, since 2×3441021203041132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (344102120304713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172051060152056 + 172051060152057.

It is an arithmetic number, because the mean of its divisors is an integer number (172051060152057).

Almost surely, 2344102120304113 is an apocalyptic number.

It is an amenable number.

344102120304113 is a deficient number, since it is larger than the sum of its proper divisors (1).

344102120304113 is an equidigital number, since it uses as much as digits as its factorization.

344102120304113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 344102120304113 its reverse (311403021201443), we get a palindrome (655505141505556).

The spelling of 344102120304113 in words is "three hundred forty-four trillion, one hundred two billion, one hundred twenty million, three hundred four thousand, one hundred thirteen".