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344113310143201 is a prime number
BaseRepresentation
bin100111000111110000001111…
…1100111010001001011100001
31200010101220121020120222022011
41032033200133213101023201
5330100423024344040301
63215511250004112521
7132324236421056524
oct11617403747211341
91603356536528264
10344113310143201
119a7106a9618905
123271756b395741
1311a019909b9001
1460d925ccd0bbb
1529bb29c036a51
hex138f81f9d12e1

344113310143201 has 2 divisors, whose sum is σ = 344113310143202. Its totient is φ = 344113310143200.

The previous prime is 344113310143177. The next prime is 344113310143241. The reversal of 344113310143201 is 102341013311443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 339513790810000 + 4599519333201 = 18425900^2 + 2144649^2 .

It is a cyclic number.

It is not a de Polignac number, because 344113310143201 - 233 = 344104720208609 is a prime.

It is a super-2 number, since 2×3441133101432012 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (344113310143241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172056655071600 + 172056655071601.

It is an arithmetic number, because the mean of its divisors is an integer number (172056655071601).

Almost surely, 2344113310143201 is an apocalyptic number.

It is an amenable number.

344113310143201 is a deficient number, since it is larger than the sum of its proper divisors (1).

344113310143201 is an equidigital number, since it uses as much as digits as its factorization.

344113310143201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 344113310143201 its reverse (102341013311443), we get a palindrome (446454323454644).

The spelling of 344113310143201 in words is "three hundred forty-four trillion, one hundred thirteen billion, three hundred ten million, one hundred forty-three thousand, two hundred one".