Base | Representation |
---|---|
bin | 1111101001100101101000… |
… | …10000100010100110001011 |
3 | 11111211222022220002101202222 |
4 | 13310302310100202212023 |
5 | 14002320442331213233 |
6 | 201105413455244255 |
7 | 10151231330156021 |
oct | 764626420424613 |
9 | 144758286071688 |
10 | 34414302210443 |
11 | aa69029467451 |
12 | 3a3988021968b |
13 | 1628340977b1c |
14 | 86d938152711 |
15 | 3ea2dd0a9898 |
hex | 1f4cb442298b |
34414302210443 has 2 divisors, whose sum is σ = 34414302210444. Its totient is φ = 34414302210442.
The previous prime is 34414302210391. The next prime is 34414302210451. The reversal of 34414302210443 is 34401220341443.
It is a strong prime.
It is an emirp because it is prime and its reverse (34401220341443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34414302210443 - 214 = 34414302194059 is a prime.
It is not a weakly prime, because it can be changed into another prime (34414302210943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17207151105221 + 17207151105222.
It is an arithmetic number, because the mean of its divisors is an integer number (17207151105222).
Almost surely, 234414302210443 is an apocalyptic number.
34414302210443 is a deficient number, since it is larger than the sum of its proper divisors (1).
34414302210443 is an equidigital number, since it uses as much as digits as its factorization.
34414302210443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 34414302210443 its reverse (34401220341443), we get a palindrome (68815522551886).
The spelling of 34414302210443 in words is "thirty-four trillion, four hundred fourteen billion, three hundred two million, two hundred ten thousand, four hundred forty-three".
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