Base | Representation |
---|---|
bin | 1010000001001010101… |
… | …11111111110101001001 |
3 | 1012220111120222220202001 |
4 | 11000211113333311021 |
5 | 21114432423301213 |
6 | 422045020111001 |
7 | 33604126250641 |
oct | 5004527776511 |
9 | 1186446886661 |
10 | 344224431433 |
11 | 122a91799193 |
12 | 56868095461 |
13 | 265ca16232c |
14 | 129367a5521 |
15 | 8e49e9e1dd |
hex | 50255ffd49 |
344224431433 has 2 divisors, whose sum is σ = 344224431434. Its totient is φ = 344224431432.
The previous prime is 344224431389. The next prime is 344224431443. The reversal of 344224431433 is 334134422443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 238757322384 + 105467109049 = 488628^2 + 324757^2 .
It is a cyclic number.
It is not a de Polignac number, because 344224431433 - 217 = 344224300361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 344224431392 and 344224431401.
It is not a weakly prime, because it can be changed into another prime (344224431443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172112215716 + 172112215717.
It is an arithmetic number, because the mean of its divisors is an integer number (172112215717).
Almost surely, 2344224431433 is an apocalyptic number.
It is an amenable number.
344224431433 is a deficient number, since it is larger than the sum of its proper divisors (1).
344224431433 is an equidigital number, since it uses as much as digits as its factorization.
344224431433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 331776, while the sum is 37.
Adding to 344224431433 its reverse (334134422443), we get a palindrome (678358853876).
The spelling of 344224431433 in words is "three hundred forty-four billion, two hundred twenty-four million, four hundred thirty-one thousand, four hundred thirty-three".
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