Base | Representation |
---|---|
bin | 1111101001111000010101… |
… | …10000101001000000000011 |
3 | 11111212221020200100200222012 |
4 | 13310330022300221000003 |
5 | 14003002023402303301 |
6 | 201114154113003135 |
7 | 10152035214653324 |
oct | 764741260510003 |
9 | 144787220320865 |
10 | 34424343400451 |
11 | aa72311455094 |
12 | 3a3b802b534ab |
13 | 1629281057684 |
14 | 87020b95844b |
15 | 3ea6c98a1ebb |
hex | 1f4f0ac29003 |
34424343400451 has 2 divisors, whose sum is σ = 34424343400452. Its totient is φ = 34424343400450.
The previous prime is 34424343400417. The next prime is 34424343400493. The reversal of 34424343400451 is 15400434342443.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34424343400451 - 218 = 34424343138307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34424343400399 and 34424343400408.
It is not a weakly prime, because it can be changed into another prime (34424343403451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17212171700225 + 17212171700226.
It is an arithmetic number, because the mean of its divisors is an integer number (17212171700226).
Almost surely, 234424343400451 is an apocalyptic number.
34424343400451 is a deficient number, since it is larger than the sum of its proper divisors (1).
34424343400451 is an equidigital number, since it uses as much as digits as its factorization.
34424343400451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1105920, while the sum is 41.
Adding to 34424343400451 its reverse (15400434342443), we get a palindrome (49824777742894).
The spelling of 34424343400451 in words is "thirty-four trillion, four hundred twenty-four billion, three hundred forty-three million, four hundred thousand, four hundred fifty-one".
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