Base | Representation |
---|---|
bin | 1010000001010100011… |
… | …00100010011010100001 |
3 | 1012220201020012010222222 |
4 | 11000222030202122201 |
5 | 21120114130012231 |
6 | 422101025440425 |
7 | 33606130606355 |
oct | 5005214423241 |
9 | 1186636163888 |
10 | 344305313441 |
11 | 123023412021 |
12 | 5688b1a0115 |
13 | 26610b40ccb |
14 | 1294341b465 |
15 | 8e5212927b |
hex | 502a3226a1 |
344305313441 has 2 divisors, whose sum is σ = 344305313442. Its totient is φ = 344305313440.
The previous prime is 344305313347. The next prime is 344305313479. The reversal of 344305313441 is 144313503443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 306356715025 + 37948598416 = 553495^2 + 194804^2 .
It is a cyclic number.
It is not a de Polignac number, because 344305313441 - 222 = 344301119137 is a prime.
It is a super-2 number, since 2×3443053134412 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (344305313741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172152656720 + 172152656721.
It is an arithmetic number, because the mean of its divisors is an integer number (172152656721).
Almost surely, 2344305313441 is an apocalyptic number.
It is an amenable number.
344305313441 is a deficient number, since it is larger than the sum of its proper divisors (1).
344305313441 is an equidigital number, since it uses as much as digits as its factorization.
344305313441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 344305313441 its reverse (144313503443), we get a palindrome (488618816884).
The spelling of 344305313441 in words is "three hundred forty-four billion, three hundred five million, three hundred thirteen thousand, four hundred forty-one".
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