Search a number
-
+
3443100121273 is a prime number
BaseRepresentation
bin110010000110101000110…
…000100111100010111001
3110012011020120022122211211
4302012220300213202321
5422402432112340043
611153423252523121
7503520142100251
oct62065060474271
913164216278754
103443100121273
11110823529110a
124773673204a1
131bc8b558ba87
14bc90b292961
155e869d93a9d
hex321a8c278b9

3443100121273 has 2 divisors, whose sum is σ = 3443100121274. Its totient is φ = 3443100121272.

The previous prime is 3443100121247. The next prime is 3443100121291. The reversal of 3443100121273 is 3721210013443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3285036626089 + 158063495184 = 1812467^2 + 397572^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3443100121273 is a prime.

It is a super-2 number, since 2×34431001212732 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3443100124273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1721550060636 + 1721550060637.

It is an arithmetic number, because the mean of its divisors is an integer number (1721550060637).

Almost surely, 23443100121273 is an apocalyptic number.

It is an amenable number.

3443100121273 is a deficient number, since it is larger than the sum of its proper divisors (1).

3443100121273 is an equidigital number, since it uses as much as digits as its factorization.

3443100121273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

The spelling of 3443100121273 in words is "three trillion, four hundred forty-three billion, one hundred million, one hundred twenty-one thousand, two hundred seventy-three".