Base | Representation |
---|---|
bin | 100111001001010001111010… |
… | …0011111101001101000010011 |
3 | 1200011010221221200112212101222 |
4 | 1032102203310133221220103 |
5 | 330112342041232422121 |
6 | 3220151453153315255 |
7 | 132345342630353006 |
oct | 11622436437515023 |
9 | 1604127850485358 |
10 | 344323040123411 |
11 | 9a791643737168 |
12 | 32750141565b2b |
13 | 11a186a5a9380b |
14 | 610547732753d |
15 | 29c19747cd0ab |
hex | 13928f47e9a13 |
344323040123411 has 2 divisors, whose sum is σ = 344323040123412. Its totient is φ = 344323040123410.
The previous prime is 344323040123383. The next prime is 344323040123441. The reversal of 344323040123411 is 114321040323443.
It is a weak prime.
It is an emirp because it is prime and its reverse (114321040323443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 344323040123411 - 218 = 344323039861267 is a prime.
It is a super-2 number, since 2×3443230401234112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (344323040123441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172161520061705 + 172161520061706.
It is an arithmetic number, because the mean of its divisors is an integer number (172161520061706).
Almost surely, 2344323040123411 is an apocalyptic number.
344323040123411 is a deficient number, since it is larger than the sum of its proper divisors (1).
344323040123411 is an equidigital number, since it uses as much as digits as its factorization.
344323040123411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 344323040123411 its reverse (114321040323443), we get a palindrome (458644080446854).
The spelling of 344323040123411 in words is "three hundred forty-four trillion, three hundred twenty-three billion, forty million, one hundred twenty-three thousand, four hundred eleven".
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