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344323040123411 is a prime number
BaseRepresentation
bin100111001001010001111010…
…0011111101001101000010011
31200011010221221200112212101222
41032102203310133221220103
5330112342041232422121
63220151453153315255
7132345342630353006
oct11622436437515023
91604127850485358
10344323040123411
119a791643737168
1232750141565b2b
1311a186a5a9380b
14610547732753d
1529c19747cd0ab
hex13928f47e9a13

344323040123411 has 2 divisors, whose sum is σ = 344323040123412. Its totient is φ = 344323040123410.

The previous prime is 344323040123383. The next prime is 344323040123441. The reversal of 344323040123411 is 114321040323443.

It is a weak prime.

It is an emirp because it is prime and its reverse (114321040323443) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 344323040123411 - 218 = 344323039861267 is a prime.

It is a super-2 number, since 2×3443230401234112 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (344323040123441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172161520061705 + 172161520061706.

It is an arithmetic number, because the mean of its divisors is an integer number (172161520061706).

Almost surely, 2344323040123411 is an apocalyptic number.

344323040123411 is a deficient number, since it is larger than the sum of its proper divisors (1).

344323040123411 is an equidigital number, since it uses as much as digits as its factorization.

344323040123411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 344323040123411 its reverse (114321040323443), we get a palindrome (458644080446854).

The spelling of 344323040123411 in words is "three hundred forty-four trillion, three hundred twenty-three billion, forty million, one hundred twenty-three thousand, four hundred eleven".