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344331621137473 is a prime number
BaseRepresentation
bin100111001001010101111001…
…1111101100111110001000001
31200011011210002201020112202121
41032102223303331213301001
5330113012130002344343
63220155432450244241
7132346065364645504
oct11622536375476101
91604153081215677
10344331621137473
119a795247475022
1232751937286681
1311a194427b5828
146105a4cc3513b
1529c1cc7ce5aed
hex1392af3f67c41

344331621137473 has 2 divisors, whose sum is σ = 344331621137474. Its totient is φ = 344331621137472.

The previous prime is 344331621137261. The next prime is 344331621137521. The reversal of 344331621137473 is 374731126133443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 255716942287104 + 88614678850369 = 15991152^2 + 9413537^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-344331621137473 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 344331621137473.

It is not a weakly prime, because it can be changed into another prime (344331621167473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172165810568736 + 172165810568737.

It is an arithmetic number, because the mean of its divisors is an integer number (172165810568737).

Almost surely, 2344331621137473 is an apocalyptic number.

It is an amenable number.

344331621137473 is a deficient number, since it is larger than the sum of its proper divisors (1).

344331621137473 is an equidigital number, since it uses as much as digits as its factorization.

344331621137473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9144576, while the sum is 52.

The spelling of 344331621137473 in words is "three hundred forty-four trillion, three hundred thirty-one billion, six hundred twenty-one million, one hundred thirty-seven thousand, four hundred seventy-three".