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34434121 is a prime number
BaseRepresentation
bin1000001101011…
…0110001001001
32101210102201211
42003112301021
532303342441
63230013121
7565454011
oct203266111
971712654
1034434121
1118489957
12b6471a1
137198327
144804c41
153052a81
hex20d6c49

34434121 has 2 divisors, whose sum is σ = 34434122. Its totient is φ = 34434120.

The previous prime is 34434097. The next prime is 34434131. The reversal of 34434121 is 12143443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33512521 + 921600 = 5789^2 + 960^2 .

It is a cyclic number.

It is not a de Polignac number, because 34434121 - 25 = 34434089 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 34434092 and 34434101.

It is not a weakly prime, because it can be changed into another prime (34434131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17217060 + 17217061.

It is an arithmetic number, because the mean of its divisors is an integer number (17217061).

Almost surely, 234434121 is an apocalyptic number.

It is an amenable number.

34434121 is a deficient number, since it is larger than the sum of its proper divisors (1).

34434121 is an equidigital number, since it uses as much as digits as its factorization.

34434121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 22.

The square root of 34434121 is about 5868.0593896108. The cubic root of 34434121 is about 325.3341604452.

Adding to 34434121 its reverse (12143443), we get a palindrome (46577564).

The spelling of 34434121 in words is "thirty-four million, four hundred thirty-four thousand, one hundred twenty-one".