Base | Representation |
---|---|
bin | 100000000100100000… |
… | …111100001111111011 |
3 | 10021212212102202200011 |
4 | 200010200330033323 |
5 | 1031010440420434 |
6 | 23452555522351 |
7 | 2326225526026 |
oct | 400440741773 |
9 | 107785382604 |
10 | 34435482619 |
11 | 13670a2884a |
12 | 68104593b7 |
13 | 332a29c725 |
14 | 194955c1bd |
15 | d68220e64 |
hex | 80483c3fb |
34435482619 has 2 divisors, whose sum is σ = 34435482620. Its totient is φ = 34435482618.
The previous prime is 34435482607. The next prime is 34435482689. The reversal of 34435482619 is 91628453443.
It is a weak prime.
It is an emirp because it is prime and its reverse (91628453443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34435482619 - 219 = 34434958331 is a prime.
It is a super-3 number, since 3×344354826193 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (34435482689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17217741309 + 17217741310.
It is an arithmetic number, because the mean of its divisors is an integer number (17217741310).
Almost surely, 234435482619 is an apocalyptic number.
34435482619 is a deficient number, since it is larger than the sum of its proper divisors (1).
34435482619 is an equidigital number, since it uses as much as digits as its factorization.
34435482619 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2488320, while the sum is 49.
The spelling of 34435482619 in words is "thirty-four billion, four hundred thirty-five million, four hundred eighty-two thousand, six hundred nineteen".
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