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3444040311442 = 21722020155721
BaseRepresentation
bin110010000111100000110…
…011001010001010010010
3110012020200002110021021221
4302013200303022022102
5422411343304431232
611154100440235254
7503552346425413
oct62074063121222
913166602407257
103444040311442
111108677a73985
1247758a16bb2a
131bca052b7713
14bc99a0b180a
155e8c26ad897
hex321e0cca292

3444040311442 has 4 divisors (see below), whose sum is σ = 5166060467166. Its totient is φ = 1722020155720.

The previous prime is 3444040311421. The next prime is 3444040311443. The reversal of 3444040311442 is 2441130404443.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3253185788281 + 190854523161 = 1803659^2 + 436869^2 .

It is a super-2 number, since 2×34440403114422 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3444040311398 and 3444040311407.

It is not an unprimeable number, because it can be changed into a prime (3444040311443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 861010077859 + ... + 861010077862.

Almost surely, 23444040311442 is an apocalyptic number.

3444040311442 is a deficient number, since it is larger than the sum of its proper divisors (1722020155724).

3444040311442 is a wasteful number, since it uses less digits than its factorization.

3444040311442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1722020155723.

The product of its (nonzero) digits is 73728, while the sum is 34.

Adding to 3444040311442 its reverse (2441130404443), we get a palindrome (5885170715885).

The spelling of 3444040311442 in words is "three trillion, four hundred forty-four billion, forty million, three hundred eleven thousand, four hundred forty-two".

Divisors: 1 2 1722020155721 3444040311442