3444805970113 has 2 divisors, whose sum is σ = 3444805970114. Its totient is φ = 3444805970112.

The previous prime is 3444805970071. The next prime is 3444805970119. The reversal of 3444805970113 is 3110795084443.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2437617096369 + 1007188873744 = 1561287^2 + 1003588^2 .

It is an emirp because it is prime and its reverse (3110795084443) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3444805970113 is a prime.

It is not a weakly prime, because it can be changed into another prime (3444805970119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1722402985056 + 1722402985057.

It is an arithmetic number, because the mean of its divisors is an integer number (1722402985057).

Almost surely, 2^{3444805970113} is an apocalyptic number.

It is an amenable number.

3444805970113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3444805970113 is an equidigital number, since it uses as much as digits as its factorization.

3444805970113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 49.

The spelling of 3444805970113 in words is "three trillion, four hundred forty-four billion, eight hundred five million, nine hundred seventy thousand, one hundred thirteen".