Base | Representation |
---|---|
bin | 110010001000011011010… |
… | …001010110010100110001 |
3 | 110012100012110100212020211 |
4 | 302020123101112110301 |
5 | 422420400423212423 |
6 | 11154342042304121 |
7 | 503615560633354 |
oct | 62103321262461 |
9 | 13170173325224 |
10 | 3445021304113 |
11 | 1109030795224 |
12 | 4778027b8041 |
13 | 1bcb305cb25c |
14 | bca504b229b |
15 | 5e92d88810d |
hex | 3221b456531 |
3445021304113 has 2 divisors, whose sum is σ = 3445021304114. Its totient is φ = 3445021304112.
The previous prime is 3445021304083. The next prime is 3445021304129. The reversal of 3445021304113 is 3114031205443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3217689739264 + 227331564849 = 1793792^2 + 476793^2 .
It is a cyclic number.
It is not a de Polignac number, because 3445021304113 - 213 = 3445021295921 is a prime.
It is not a weakly prime, because it can be changed into another prime (3445021304173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1722510652056 + 1722510652057.
It is an arithmetic number, because the mean of its divisors is an integer number (1722510652057).
Almost surely, 23445021304113 is an apocalyptic number.
It is an amenable number.
3445021304113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3445021304113 is an equidigital number, since it uses as much as digits as its factorization.
3445021304113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 3445021304113 its reverse (3114031205443), we get a palindrome (6559052509556).
The spelling of 3445021304113 in words is "three trillion, four hundred forty-five billion, twenty-one million, three hundred four thousand, one hundred thirteen".
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