Base | Representation |
---|---|
bin | 110010001101000100110… |
… | …100000111101100111101 |
3 | 110012211002100121002221220 |
4 | 302031010310013230331 |
5 | 423011111343034123 |
6 | 11200525245143553 |
7 | 504153354534450 |
oct | 62150464075475 |
9 | 13184070532856 |
10 | 3450013252413 |
11 | 11101625a2932 |
12 | 47877655abb9 |
13 | 1c044789b010 |
14 | bcda5479497 |
15 | 5eb21c4dce3 |
hex | 32344d07b3d |
3450013252413 has 32 divisors (see below), whose sum is σ = 5799647062272. Its totient is φ = 1775402150400.
The previous prime is 3450013252403. The next prime is 3450013252529. The reversal of 3450013252413 is 3142523100543.
3450013252413 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3450013252413 - 26 = 3450013252349 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3450013252403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 154103578 + ... + 154125963.
It is an arithmetic number, because the mean of its divisors is an integer number (181238970696).
Almost surely, 23450013252413 is an apocalyptic number.
It is an amenable number.
3450013252413 is a deficient number, since it is larger than the sum of its proper divisors (2349633809859).
3450013252413 is a wasteful number, since it uses less digits than its factorization.
3450013252413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 308229605.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 3450013252413 its reverse (3142523100543), we get a palindrome (6592536352956).
The spelling of 3450013252413 in words is "three trillion, four hundred fifty billion, thirteen million, two hundred fifty-two thousand, four hundred thirteen".
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