Base | Representation |
---|---|
bin | 110010001101001010000… |
… | …100001000000011100001 |
3 | 110012211022111100010111211 |
4 | 302031022010020003201 |
5 | 423011301420143431 |
6 | 11200542113110121 |
7 | 504155504321002 |
oct | 62151204100341 |
9 | 13184274303454 |
10 | 3450101334241 |
11 | 11101a8294031 |
12 | 47879bb58341 |
13 | 1c045cbcab43 |
14 | bcdb30471a9 |
15 | 5eb2984c2b1 |
hex | 3234a1080e1 |
3450101334241 has 2 divisors, whose sum is σ = 3450101334242. Its totient is φ = 3450101334240.
The previous prime is 3450101334227. The next prime is 3450101334247. The reversal of 3450101334241 is 1424331010543.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2522684183616 + 927417150625 = 1588296^2 + 963025^2 .
It is a cyclic number.
It is not a de Polignac number, because 3450101334241 - 25 = 3450101334209 is a prime.
It is not a weakly prime, because it can be changed into another prime (3450101334247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1725050667120 + 1725050667121.
It is an arithmetic number, because the mean of its divisors is an integer number (1725050667121).
Almost surely, 23450101334241 is an apocalyptic number.
It is an amenable number.
3450101334241 is a deficient number, since it is larger than the sum of its proper divisors (1).
3450101334241 is an equidigital number, since it uses as much as digits as its factorization.
3450101334241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 3450101334241 its reverse (1424331010543), we get a palindrome (4874432344784).
The spelling of 3450101334241 in words is "three trillion, four hundred fifty billion, one hundred one million, three hundred thirty-four thousand, two hundred forty-one".
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