Base | Representation |
---|---|
bin | 100000001000011111… |
… | …001100100110001001 |
3 | 10022001111212000101111 |
4 | 200020133030212021 |
5 | 1031130021243103 |
6 | 23503340250321 |
7 | 2330665205254 |
oct | 401037144611 |
9 | 108044760344 |
10 | 34502134153 |
11 | 136a5612063 |
12 | 682a8409a1 |
13 | 333b0380c6 |
14 | 195434c09b |
15 | d6ded986d |
hex | 8087cc989 |
34502134153 has 2 divisors, whose sum is σ = 34502134154. Its totient is φ = 34502134152.
The previous prime is 34502134141. The next prime is 34502134171. The reversal of 34502134153 is 35143120543.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32534058384 + 1968075769 = 180372^2 + 44363^2 .
It is a cyclic number.
It is not a de Polignac number, because 34502134153 - 213 = 34502125961 is a prime.
It is a super-2 number, since 2×345021341532 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34502134123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17251067076 + 17251067077.
It is an arithmetic number, because the mean of its divisors is an integer number (17251067077).
Almost surely, 234502134153 is an apocalyptic number.
It is an amenable number.
34502134153 is a deficient number, since it is larger than the sum of its proper divisors (1).
34502134153 is an equidigital number, since it uses as much as digits as its factorization.
34502134153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 34502134153 its reverse (35143120543), we get a palindrome (69645254696).
The spelling of 34502134153 in words is "thirty-four billion, five hundred two million, one hundred thirty-four thousand, one hundred fifty-three".
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