Base | Representation |
---|---|
bin | 1010000010101010111… |
… | …11010110100110110001 |
3 | 1012222120211221200112012 |
4 | 11001111133112212301 |
5 | 21123111101303342 |
6 | 422301054012305 |
7 | 33633130525526 |
oct | 5012537264661 |
9 | 1188524850465 |
10 | 345031666097 |
11 | 123366420578 |
12 | 56a524a7095 |
13 | 266c8479191 |
14 | 129b1a9514d |
15 | 8e95ca4b82 |
hex | 50557d69b1 |
345031666097 has 2 divisors, whose sum is σ = 345031666098. Its totient is φ = 345031666096.
The previous prime is 345031666051. The next prime is 345031666117. The reversal of 345031666097 is 790666130543.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 216172923136 + 128858742961 = 464944^2 + 358969^2 .
It is a cyclic number.
It is not a de Polignac number, because 345031666097 - 28 = 345031665841 is a prime.
It is not a weakly prime, because it can be changed into another prime (345031666597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172515833048 + 172515833049.
It is an arithmetic number, because the mean of its divisors is an integer number (172515833049).
Almost surely, 2345031666097 is an apocalyptic number.
It is an amenable number.
345031666097 is a deficient number, since it is larger than the sum of its proper divisors (1).
345031666097 is an equidigital number, since it uses as much as digits as its factorization.
345031666097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 50.
The spelling of 345031666097 in words is "three hundred forty-five billion, thirty-one million, six hundred sixty-six thousand, ninety-seven".
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