Base | Representation |
---|---|
bin | 110010001110000000101… |
… | …101110010001000010011 |
3 | 110012220200101121222000020 |
4 | 302032000231302020103 |
5 | 423020141131133042 |
6 | 11201213105154523 |
7 | 504220306623264 |
oct | 62160055621023 |
9 | 13186611558006 |
10 | 3451018224147 |
11 | 1110628901a8a |
12 | 4789b702ba43 |
13 | 1c0577b59150 |
14 | bd05cb1c96b |
15 | 5eb800b33ec |
hex | 32380b72213 |
3451018224147 has 64 divisors (see below), whose sum is σ = 5317723353600. Its totient is φ = 1972783088640.
The previous prime is 3451018224107. The next prime is 3451018224149. The reversal of 3451018224147 is 7414228101543.
It is not a de Polignac number, because 3451018224147 - 27 = 3451018224019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3451018224099 and 3451018224108.
It is not an unprimeable number, because it can be changed into a prime (3451018224149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 67563304 + ... + 67614362.
It is an arithmetic number, because the mean of its divisors is an integer number (83089427400).
Almost surely, 23451018224147 is an apocalyptic number.
3451018224147 is a deficient number, since it is larger than the sum of its proper divisors (1866705129453).
3451018224147 is a wasteful number, since it uses less digits than its factorization.
3451018224147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52868.
The product of its (nonzero) digits is 215040, while the sum is 42.
The spelling of 3451018224147 in words is "three trillion, four hundred fifty-one billion, eighteen million, two hundred twenty-four thousand, one hundred forty-seven".
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