Base | Representation |
---|---|
bin | 100000001000111101… |
… | …111101111000001011 |
3 | 10022002002000211002211 |
4 | 200020331331320023 |
5 | 1031134102402311 |
6 | 23504225205551 |
7 | 2331123601645 |
oct | 401075757013 |
9 | 108062024084 |
10 | 34510200331 |
11 | 136aa121322 |
12 | 68314908b7 |
13 | 333c9006a9 |
14 | 195544b895 |
15 | d6ea7e821 |
hex | 808f7de0b |
34510200331 has 2 divisors, whose sum is σ = 34510200332. Its totient is φ = 34510200330.
The previous prime is 34510200313. The next prime is 34510200377. The reversal of 34510200331 is 13300201543.
34510200331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with previous prime (34510200313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 34510200331 - 25 = 34510200299 is a prime.
It is a super-2 number, since 2×345102003312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34510203331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17255100165 + 17255100166.
It is an arithmetic number, because the mean of its divisors is an integer number (17255100166).
Almost surely, 234510200331 is an apocalyptic number.
34510200331 is a deficient number, since it is larger than the sum of its proper divisors (1).
34510200331 is an equidigital number, since it uses as much as digits as its factorization.
34510200331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 34510200331 its reverse (13300201543), we get a palindrome (47810401874).
The spelling of 34510200331 in words is "thirty-four billion, five hundred ten million, two hundred thousand, three hundred thirty-one".
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