3451300241 has 2 divisors, whose sum is σ = 3451300242. Its totient is φ = 3451300240.

The previous prime is 3451300231. The next prime is 3451300249. The reversal of 3451300241 is 1420031543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3436890625 + 14409616 = 58625^2 + 3796^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3451300241 is a prime.

It is a super-3 number, since 3×3451300241³ (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3451300249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1725650120 + 1725650121.

It is an arithmetic number, because the mean of its divisors is an integer number (1725650121).

Almost surely, 2^3451300241 is an apocalyptic number.

It is an amenable number.

3451300241 is a deficient number, since it is larger than the sum of its proper divisors (1).

3451300241 is an equidigital number, since it uses as much as digits as its factorization.

3451300241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3451300241 is about 58747.7679661108. The cubic root of 3451300241 is about 1511.2196104030.

Adding to 3451300241 its reverse (1420031543), we get a palindrome (4871331784).

The spelling of 3451300241 in words is "three billion, four hundred fifty-one million, three hundred thousand, two hundred forty-one".