34513154041 has 2 divisors, whose sum is σ = 34513154042. Its totient is φ = 34513154040.

The previous prime is 34513154003. The next prime is 34513154063. The reversal of 34513154041 is 14045131543.

34513154041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32862438400 + 1650715641 = 181280^2 + 40629^2 .

It is a cyclic number.

It is not a de Polignac number, because 34513154041 - 2⁹ = 34513153529 is a prime.

It is a super-3 number, since 3×34513154041³ (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 34513153994 and 34513154012.

It is not a weakly prime, because it can be changed into another prime (34513154141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17256577020 + 17256577021.

It is an arithmetic number, because the mean of its divisors is an integer number (17256577021).

Almost surely, 2^34513154041 is an apocalyptic number.

It is an amenable number.

34513154041 is a deficient number, since it is larger than the sum of its proper divisors (1).

34513154041 is an equidigital number, since it uses as much as digits as its factorization.

34513154041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 34513154041 its reverse (14045131543), we get a palindrome (48558285584).

The spelling of 34513154041 in words is "thirty-four billion, five hundred thirteen million, one hundred fifty-four thousand, forty-one".