Base | Representation |
---|---|
bin | 1010000010111010101… |
… | …01111010010000111001 |
3 | 1012222221000211220001021 |
4 | 11001131111322100321 |
5 | 21123343313032231 |
6 | 422322121422441 |
7 | 33636320364145 |
oct | 5013525722071 |
9 | 1188830756037 |
10 | 345163408441 |
11 | 123423822545 |
12 | 56a8a63aa21 |
13 | 26719854a27 |
14 | 129c538a225 |
15 | 8ea2629811 |
hex | 505d57a439 |
345163408441 has 2 divisors, whose sum is σ = 345163408442. Its totient is φ = 345163408440.
The previous prime is 345163408423. The next prime is 345163408481. The reversal of 345163408441 is 144804361543.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 289610804025 + 55552604416 = 538155^2 + 235696^2 .
It is a cyclic number.
It is not a de Polignac number, because 345163408441 - 27 = 345163408313 is a prime.
It is not a weakly prime, because it can be changed into another prime (345163408481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172581704220 + 172581704221.
It is an arithmetic number, because the mean of its divisors is an integer number (172581704221).
Almost surely, 2345163408441 is an apocalyptic number.
It is an amenable number.
345163408441 is a deficient number, since it is larger than the sum of its proper divisors (1).
345163408441 is an equidigital number, since it uses as much as digits as its factorization.
345163408441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 552960, while the sum is 43.
Adding to 345163408441 its reverse (144804361543), we get a palindrome (489967769984).
The spelling of 345163408441 in words is "three hundred forty-five billion, one hundred sixty-three million, four hundred eight thousand, four hundred forty-one".
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