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3453545451217 is a prime number
BaseRepresentation
bin110010010000010111010…
…110011000111011010001
3110020011012112001101210211
4302100113112120323101
5423040330113414332
611202311544324121
7504340034661241
oct62202726307321
913204175041724
103453545451217
1111117054120a4
124793a1473641
131c088b5cc394
14bd21c619b21
155ec7bdbb447
hex32417598ed1

3453545451217 has 2 divisors, whose sum is σ = 3453545451218. Its totient is φ = 3453545451216.

The previous prime is 3453545451149. The next prime is 3453545451269. The reversal of 3453545451217 is 7121545453543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2902631171521 + 550914279696 = 1703711^2 + 742236^2 .

It is an emirp because it is prime and its reverse (7121545453543) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3453545451217 is a prime.

It is not a weakly prime, because it can be changed into another prime (3453545451277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1726772725608 + 1726772725609.

It is an arithmetic number, because the mean of its divisors is an integer number (1726772725609).

Almost surely, 23453545451217 is an apocalyptic number.

It is an amenable number.

3453545451217 is a deficient number, since it is larger than the sum of its proper divisors (1).

3453545451217 is an equidigital number, since it uses as much as digits as its factorization.

3453545451217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5040000, while the sum is 49.

The spelling of 3453545451217 in words is "three trillion, four hundred fifty-three billion, five hundred forty-five million, four hundred fifty-one thousand, two hundred seventeen".