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3454232214113 is a prime number
BaseRepresentation
bin110010010001000000010…
…010001011101001100001
3110020012222101022120101122
4302101000102023221201
5423043231421322423
611202504040142025
7504363044241362
oct62210022135141
913205871276348
103454232214113
111111a2804023a
12479553467915
131c096a985665
14bd285909b69
155ecbc3268c8
hex3244048ba61

3454232214113 has 2 divisors, whose sum is σ = 3454232214114. Its totient is φ = 3454232214112.

The previous prime is 3454232214047. The next prime is 3454232214119. The reversal of 3454232214113 is 3114122324543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2827297642849 + 626934571264 = 1681457^2 + 791792^2 .

It is an emirp because it is prime and its reverse (3114122324543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3454232214113 - 230 = 3453158472289 is a prime.

It is not a weakly prime, because it can be changed into another prime (3454232214119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1727116107056 + 1727116107057.

It is an arithmetic number, because the mean of its divisors is an integer number (1727116107057).

Almost surely, 23454232214113 is an apocalyptic number.

It is an amenable number.

3454232214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3454232214113 is an equidigital number, since it uses as much as digits as its factorization.

3454232214113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 35.

Adding to 3454232214113 its reverse (3114122324543), we get a palindrome (6568354538656).

The spelling of 3454232214113 in words is "three trillion, four hundred fifty-four billion, two hundred thirty-two million, two hundred fourteen thousand, one hundred thirteen".