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34545241305409 is a prime number
BaseRepresentation
bin1111101101011001100001…
…10101100011000101000001
311112022111022021002121111211
413312230300311203011001
514011442123233233114
6201245510442410121
710163545166130412
oct766546065430501
9145274267077454
1034545241305409
111000961114051a
123a5b123500941
1316377aa283943
14875dda233809
153ed9035bd6c4
hex1f6b30d63141

34545241305409 has 2 divisors, whose sum is σ = 34545241305410. Its totient is φ = 34545241305408.

The previous prime is 34545241305389. The next prime is 34545241305451. The reversal of 34545241305409 is 90450314254543.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34157560735809 + 387680569600 = 5844447^2 + 622640^2 .

It is an emirp because it is prime and its reverse (90450314254543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34545241305409 - 233 = 34536651370817 is a prime.

It is a super-2 number, since 2×345452413054092 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (34545241302409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17272620652704 + 17272620652705.

It is an arithmetic number, because the mean of its divisors is an integer number (17272620652705).

Almost surely, 234545241305409 is an apocalyptic number.

It is an amenable number.

34545241305409 is a deficient number, since it is larger than the sum of its proper divisors (1).

34545241305409 is an equidigital number, since it uses as much as digits as its factorization.

34545241305409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184000, while the sum is 49.

The spelling of 34545241305409 in words is "thirty-four trillion, five hundred forty-five billion, two hundred forty-one million, three hundred five thousand, four hundred nine".