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34545522040153 is a prime number
BaseRepresentation
bin1111101101011010000011…
…00100011101110101011001
311112022112000211100102011221
413312231001210131311121
514011443212120241103
6201245554351452041
710163555145261145
oct766550144356531
9145275024312157
1034545522040153
1110009745656703
123a5b1a1527021
131637823497887
14876025630225
153ed91d0741bd
hex1f6b4191dd59

34545522040153 has 2 divisors, whose sum is σ = 34545522040154. Its totient is φ = 34545522040152.

The previous prime is 34545522040147. The next prime is 34545522040219. The reversal of 34545522040153 is 35104022554543.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26723140930249 + 7822381109904 = 5169443^2 + 2796852^2 .

It is a cyclic number.

It is not a de Polignac number, because 34545522040153 - 25 = 34545522040121 is a prime.

It is not a weakly prime, because it can be changed into another prime (34545522070153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17272761020076 + 17272761020077.

It is an arithmetic number, because the mean of its divisors is an integer number (17272761020077).

Almost surely, 234545522040153 is an apocalyptic number.

It is an amenable number.

34545522040153 is a deficient number, since it is larger than the sum of its proper divisors (1).

34545522040153 is an equidigital number, since it uses as much as digits as its factorization.

34545522040153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440000, while the sum is 43.

Adding to 34545522040153 its reverse (35104022554543), we get a palindrome (69649544594696).

The spelling of 34545522040153 in words is "thirty-four trillion, five hundred forty-five billion, five hundred twenty-two million, forty thousand, one hundred fifty-three".