Base | Representation |
---|---|
bin | 100111010001111011010110… |
… | …0010100110001011011101001 |
3 | 1200022100120122221211000110020 |
4 | 1032203312230110301123221 |
5 | 330241330111011100400 |
6 | 3222501450312511053 |
7 | 132530245636313325 |
oct | 11643665424613351 |
9 | 1608316587730406 |
10 | 345511535253225 |
11 | a00aa68a201a80 |
12 | 3290254a0ab489 |
13 | 11aa37a0985113 |
14 | 6146bc18bc985 |
15 | 29e283444d2a0 |
hex | 13a3dac5316e9 |
345511535253225 has 24 divisors (see below), whose sum is σ = 623177169040032. Its totient is φ = 167520744364800.
The previous prime is 345511535253217. The next prime is 345511535253239. The reversal of 345511535253225 is 522352535115543.
It is not a de Polignac number, because 345511535253225 - 23 = 345511535253217 is a prime.
It is a super-3 number, since 3×3455115352532253 (a number of 45 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 209400929632 + ... + 209400931281.
It is an arithmetic number, because the mean of its divisors is an integer number (25965715376668).
Almost surely, 2345511535253225 is an apocalyptic number.
It is an amenable number.
345511535253225 is a deficient number, since it is larger than the sum of its proper divisors (277665633786807).
345511535253225 is a wasteful number, since it uses less digits than its factorization.
345511535253225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418801860937 (or 418801860932 counting only the distinct ones).
The product of its digits is 13500000, while the sum is 51.
The spelling of 345511535253225 in words is "three hundred forty-five trillion, five hundred eleven billion, five hundred thirty-five million, two hundred fifty-three thousand, two hundred twenty-five".
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