3465140113 has 2 divisors, whose sum is σ = 3465140114. Its totient is φ = 3465140112.

The previous prime is 3465140101. The next prime is 3465140131. The reversal of 3465140113 is 3110415643.

Together with next prime (3465140131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2155930624 + 1309209489 = 46432^2 + 36183^2 .

It is an emirp because it is prime and its reverse (3110415643) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3465140113 is a prime.

It is not a weakly prime, because it can be changed into another prime (3465140183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1732570056 + 1732570057.

It is an arithmetic number, because the mean of its divisors is an integer number (1732570057).

Almost surely, 2^3465140113 is an apocalyptic number.

It is an amenable number.

3465140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3465140113 is an equidigital number, since it uses as much as digits as its factorization.

3465140113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

The square root of 3465140113 is about 58865.4407356303. The cubic root of 3465140113 is about 1513.2369362234.

Adding to 3465140113 its reverse (3110415643), we get a palindrome (6575555756).

The spelling of 3465140113 in words is "three billion, four hundred sixty-five million, one hundred forty thousand, one hundred thirteen".