Base | Representation |
---|---|
bin | 100000010110110000… |
… | …110011110110110001 |
3 | 10022200012111210021011 |
4 | 200112300303312301 |
5 | 1032122324214213 |
6 | 23543213430521 |
7 | 2336634001054 |
oct | 402660636661 |
9 | 108605453234 |
10 | 34741632433 |
11 | 13808822722 |
12 | 6896a9b441 |
13 | 3378841771 |
14 | 1978092a9b |
15 | d8504703d |
hex | 816c33db1 |
34741632433 has 2 divisors, whose sum is σ = 34741632434. Its totient is φ = 34741632432.
The previous prime is 34741632427. The next prime is 34741632437. The reversal of 34741632433 is 33423614743.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23587737889 + 11153894544 = 153583^2 + 105612^2 .
It is a cyclic number.
It is not a de Polignac number, because 34741632433 - 225 = 34708078001 is a prime.
It is not a weakly prime, because it can be changed into another prime (34741632437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17370816216 + 17370816217.
It is an arithmetic number, because the mean of its divisors is an integer number (17370816217).
Almost surely, 234741632433 is an apocalyptic number.
It is an amenable number.
34741632433 is a deficient number, since it is larger than the sum of its proper divisors (1).
34741632433 is an equidigital number, since it uses as much as digits as its factorization.
34741632433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 435456, while the sum is 40.
The spelling of 34741632433 in words is "thirty-four billion, seven hundred forty-one million, six hundred thirty-two thousand, four hundred thirty-three".
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