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3478404406523 is a prime number
BaseRepresentation
bin110010100111100001000…
…011110001110011111011
3110022112100222120011200012
4302213201003301303323
5423442233012002043
611221542410132135
7506210050421504
oct62474103616373
913275328504605
103478404406523
111121201673162
1248217a72104b
131c3020850ba7
14c04d9d69bab
15607344cca18
hex329e10f1cfb

3478404406523 has 2 divisors, whose sum is σ = 3478404406524. Its totient is φ = 3478404406522.

The previous prime is 3478404406447. The next prime is 3478404406601. The reversal of 3478404406523 is 3256044048743.

3478404406523 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (3256044048743) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3478404406523 - 218 = 3478404144379 is a prime.

It is not a weakly prime, because it can be changed into another prime (3478404406423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1739202203261 + 1739202203262.

It is an arithmetic number, because the mean of its divisors is an integer number (1739202203262).

Almost surely, 23478404406523 is an apocalyptic number.

3478404406523 is a deficient number, since it is larger than the sum of its proper divisors (1).

3478404406523 is an equidigital number, since it uses as much as digits as its factorization.

3478404406523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7741440, while the sum is 50.

The spelling of 3478404406523 in words is "three trillion, four hundred seventy-eight billion, four hundred four million, four hundred six thousand, five hundred twenty-three".