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3479481990713 is a prime number
BaseRepresentation
bin110010101000100001010…
…010011011111000111001
3110022122011002020010021202
4302220201102123320321
5424001434342200323
611222241342343545
7506245543634411
oct62504122337071
913278132203252
103479481990713
111121704968103
1248241b58abb5
131c3162b83981
14c059d111641
1560798dd6d28
hex32a2149be39

3479481990713 has 2 divisors, whose sum is σ = 3479481990714. Its totient is φ = 3479481990712.

The previous prime is 3479481990623. The next prime is 3479481990739. The reversal of 3479481990713 is 3170991849743.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3328625100304 + 150856890409 = 1824452^2 + 388403^2 .

It is a cyclic number.

It is not a de Polignac number, because 3479481990713 - 214 = 3479481974329 is a prime.

It is a super-2 number, since 2×34794819907132 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3479481990713.

It is not a weakly prime, because it can be changed into another prime (3479481990913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1739740995356 + 1739740995357.

It is an arithmetic number, because the mean of its divisors is an integer number (1739740995357).

Almost surely, 23479481990713 is an apocalyptic number.

It is an amenable number.

3479481990713 is a deficient number, since it is larger than the sum of its proper divisors (1).

3479481990713 is an equidigital number, since it uses as much as digits as its factorization.

3479481990713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41150592, while the sum is 65.

The spelling of 3479481990713 in words is "three trillion, four hundred seventy-nine billion, four hundred eighty-one million, nine hundred ninety thousand, seven hundred thirteen".